F(x)=15+2x^2

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Solution for F(x)=15+2x^2 equation: 



(F)=15+2F^2

We move all terms to the left:

(F)-(15+2F^2)=0

We get rid of parentheses

-2F^2+F-15=0

a = -2; b = 1; c = -15;
Δ = b2-4ac
Δ = 12-4·(-2)·(-15)
Δ = -119
Delta is less than zero, so there is no solution for the equation

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